import re


def is_guid_file(filename):
    # GUID的正则表达式
    guid_pattern = r'^[a-fA-F0-9]{8}-[a-fA-F0-9]{4}-[a-fA-F0-9]{4}-[a-fA-F0-9]{4}-[a-fA-F0-9]{12}\.[a-fA-F0-9]*?'
    # 使用re.match检查文件名是否匹配GUID模式
    if re.match(guid_pattern, filename):
        return True
    else:
        return False